6th Grade Math Textbook, Fundamentals

(Marvins-Underground-K-12) #1
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3-5


Update your skills. See page 412 XII.

Solve Inequalities Using Multiplication


Objective To solve one-step inequalities by applying the Multiplication Property
of Inequality • To graph the solution set of an inequality

Five friends evenly divided the cost of a trip to Yosemite
National Park. Each friend paid a whole dollar amount
that was at most $13. What was the total cost of the trip?


To find the total cost of the trip, write and solve an inequality.

Let c the total cost of the trip.

total cost divided by number of friends is at most cost per friend

c  5 $13
Solve inequalities involving division the same way that you
solve division equations.

Solve: 
13

(5) 13(5)

13 • 5 Simplify.

c 
65
So the solution set is the whole numbers less than 65.

Check: According to the solution set, 65 is a solution and 70 is not.

13 Substitute 65 for c. 13 Substitute 70 for c.

13 
13 Tr u e 14
13 False
The total cost of the trip was whole dollar amounts of $65 or less.

When an inequality is multiplied by a negative number,

the symbol must be reversed to form a true statement.

Solve:  12

(3) 12(3)

p 36 Simplify.
So the solution set is all numbers greater than 36.
Check: According to the solution set,
33 is a solution and 36 is not.

12 Substitute 33 for p. 12 Substitute 36 for p.

11  12 Tr u e 12  12 False

 36
 3

 33
 3

p
 3
p
 3

70
5

65
5
??

c
5

5
5

1

1

c

? ?

Multiply both sides by  3
to isolate pand reverse the
inequality symbol.

c
5 Multiply both sides
by 5 to isolate c.

Key Concept
Multiplication Property of Inequality
(multiply by a positive number)
When you multiply both sides of an
inequality by the same positive
number, you get a true statement.
If aband cis positive, then acbc.
A similar statement can be written for
ab, a b, and a b.

Key Concept
Multiplication Property of Inequality
(multiply by a negative number)
When you multiply both sides of an
inequality by the same negativenumber
andyou reverse the inequality symbol,
you get a true statement.
If aband cis negative, then acbc.
A similar statement can be written for
ab, a b, and a b.

Think

5 cmeans c^5
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