16.2 CHAPTER 16. GEOMETRY
SOLUTION
Step 1 : Draw a picture
r
h
r
a h
Step 2 : Identify the faces thatmake up the cone
The cone has two faces:the base and the walls.The base is a circle of radius r
and the walls can be opened out to a sector of acircle.
a
2 πr = circumference
This curved surface canbe cut into many thin triangles with height closeto a (a is
called the slant height). The area of these triangles will add up to^12 ×base×height(of
a small triangle) which is^12 × 2 πr× a = πra
Step 3 : Calculate a
a can be calculated by using the Theorem of Pythagoras. Therefore:
a =
�
r^2 + h^2
Step 4 : Calculate the area of the circular base
Ab= πr^2
Step 5 : Calculate the area of the curved walls
Aw = πra
= πr
�
r^2 + h^2
Step 6 : Calculate surface area A
A = Ab+ Aw
= πr^2 + πr
�
r^2 + h^2