16.5 CHAPTER 16. GEOMETRY
1
2
3
1 2 3
θ
Δy
Δx
x
y
1
2
3
1 2 3 4
f(x) = 4x− 4
g(x) = 2x− 2
θg θf
x
y
(a) (b)
Figure 16.4: (a) A line makes an angle θ with the x-axis. (b) The angle is dependent on the gradient. If
the gradient of f is mfand the gradient of g is mgthen mf> mgand θf> θg.
Firstly, we note that if the gradient changes, thenthe value of θ changes (Figure 16.4(b)), so we suspect
that the inclination of aline is related to the gradient. We know that thegradient is a ratio of a change
in the y-direction to a change inthe x-direction.
m =
Δy
Δx
But, in Figure 16.4(a) wesee that
tan θ =
Δy
Δx
∴ m = tan θ
For example, to find theinclination of the line y = x, we know m = 1
∴ tan θ = 1
∴ θ = 45◦
Exercise 16 - 3
- Find the equations of the following lines
(a) through points (−1;3) and (1;4)
(b) through points (7;−3) and (0;4)
(c) parallel to y =^12 x + 3 passing through (−1;3)
(d) perpendicular to y =−^12 x + 3 passing through (−1;2)
(e) perpendicular to 2 y + x = 6 passing through the origin
- Find the inclination of the following lines
(a) y = 2x− 3
(b) y =^13 x− 7
(c) 4 y = 3x + 8
(d) y =−^23 x + 3 (Hint: if m is negative θ must be in the second quadrant)
(e) 3 y + x− 3 = 0
- Show that the line y = k for any constant k is parallel to the x-axis. (Hint: Show that the
inclination of this line is 0 ◦.)