CHAPTER 10. TRIGONOMETRY 10.2
we have that
cos(α−β) = sin(90− (α−β))
= sin((90−α) +β))
= sin(90−α) cosβ + cos(90−α) sinβ
= cosα cosβ + sinα sinβ
Derivation ofsin2α EMCCK
We know that
sin(α +β) = sinα cosβ + cosα sinβ
When α = β, we have that
sin(2α) = sin(α +α) = sinα cosα + cosα sinα
= 2 sinα cosα
Derivation ofcos2α EMCCL
We know that
cos(α +β) = cosα cosβ− sinα sinβ
When α = β, we have that
cos(2α) = cos(α +α) = cosα cosα− sinα sinα
= cos^2 α− sin^2 α
However, we can also write
cos 2α = 2 cos^2 α− 1
and
cos 2α = 1− 2 sin^2 α
by using
sin^2 α + cos^2 α = 1.
Activity: Thecos2α Identity
Use
sin^2 α + cos^2 α = 1
to show that:
cos 2α = 2 cos^2 α− 1 = 1− 2 sin^2 α