Everything Maths Grade 12

(Marvins-Underground-K-12) #1

CHAPTER 2. LOGARITHMS 2.10


3 log 3 + log 125 = 3 log 3 + log 5^3
= 3 log 3 + 3 log 5∵ loga(xb) = b loga(x)
= 3 log 15 (Logarithm Law 3)
Step 3 : Final Answer
We cannot simplify anyfurther. The final answer is:

3 log 15

Example 2: Simplification of Logs


QUESTION

Simplify, without use ofa calculator:

8

(^23)



  • log 232
    SOLUTION
    Step 1 : Try to write any quantities as exponents
    8 can be written as 23. 32 can be written as 25.
    Step 2 : Re-write the question using the exponential forms of the numbers
    8
    (^23)

  • log 2 32 = (2^3 )
    (^23)

  • log 225
    Step 3 : Determine which lawscan be used.
    We can use:
    loga(xb) = b loga(x)
    Step 4 : Apply log laws to simplify
    (2^3 )
    2
    (^3) + log 225 = (2)^3 ×
    2
    (^3) + 5 log 22
    Step 5 : Determine which lawscan be used.
    We can now use logaa = 1
    Step 6 : Apply log laws to simplify
    (2)^2 + 5 log 2 2 = 2^2 + 5(1) = 4 + 5 = 9
    Step 7 : Final Answer
    The final answer is:
    8
    2
    (^3) + log 2 32 = 9

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