CHAPTER 6. FUNCTIONS AND GRAPHS 6.4
By setting x = 0 we have that the y-intercept is yint=−qa. Similarly, by setting y = 0 we have that
the x-intercept is xint= q.
It is interesting to note that if f (x) = ax +q, then f−^1 (x) =^1 ax−qaand the y-intercept of f (x) is the
x-intercept of f−^1 (x) and the x-intercept of f (x) is the y-intercept of f−^1 (x).
Exercise 6 - 2
- Given f (x) = 2x− 3 , find f−^1 (x)
- Consider the function f (x) = 3x− 7.
(a) Is the relation a function?(b) If it is a function, identify the domain and range.- Sketch the graph of the function f (x) = 3x− 1 and its inverse on the same set of axes.
- The inverse of a function is f−^1 (x) = 2x− 4 , what is the function f (x)?
More practice video solutions or help at http://www.everythingmaths.co.za(1.) 01f0 (2.) 01f1 (3.) 01f2 (4.) 01f3Inverse Function ofy=ax
(^2) EMCAY
The inverse relation, possibly a function, of y = ax^2 is determined by solvingfor x as:
y = ax^2 (6.9)
x^2 =
y
a
(6.10)
x =±�
y
a