CHAPTER 7. DIFFERENTIAL CALCULUS 7.3
Example 7: Derivatives - First Principles
QUESTION
Calculate the derivativeof g(x) = x− 1 from first principles.
SOLUTION
Step 1 : Calculate the gradientat a point
We know that the gradient at a point x is given by:
g�(x) = lim
h→ 0
g(x +h)−g(x)
h
Step 2 : Write g(x +h) and simplify
g(x +h) = x +h− 1
Step 3 : Calculate limit
g�(x) = lim
h→ 0
g(x +h)−g(x)
h
= lim
h→ 0
x +h− 1 − (x− 1)
h
= lim
h→ 0
x +h− 1 −x + 1
h
= lim
h→ 0
h
h
= lim
h→ 0
1
= 1
Step 4 : Write the final answer
The derivative g�(x) of g(x) = x− 1 is 1.
Exercise 7 - 2
- Given g(x) =−x^2
(a) determine
g(x +h)−g(x)
h
(b) hence, determine
lim
h→ 0
g(x +h)−g(x)
h
(c) explain the meaningof your answer in (b).
- Find the derivative of f (x) =− 2 x^2 + 3x using first principles.