Cracking the SAT Chemistry Subject Test

(Marvins-Underground-K-12) #1


  1.      Each    period  (horizontal row)    of  the periodic    table   corresponds to  an

    energy shell. For example, atoms of carbon, C, (row 2 ) have outer electrons
    in the 2nd energy shell; atoms of sodium, Na, (row 3 ) have outer electrons
    in the 3rd energy shell, and so on.



  2. When writing electron configurations, and determining which subshells
    to fill, be aware of what area and row the element is in. Then remember the
    following points:
    • An element in the s area of row n has outer electrons in the n
    subshell.
    • An element in the p area of row n has outer electrons in the np
    subshell.
    • An element in the d area of row n has outer electrons in the (n
    − 1)d subshell.
    • An element in the f area of row n has outer electrons in the (n
    − 2)f subshell.


Let’s put it all together and try writing the electron configuration for an atom of
fluorine.


Step    1.          Where   do  we  start?  At  hydrogen,   of  course. It’s    in  the s   area    of
row 1. Hydrogen (H) has an electron in its 1s subshell. Remember that
although helium looks like it is in the p area, it is actually part of the 1s
area.

How Does    This    Work?
Consider an atom of phosphorus, P, (row 3). It’s in
the p area, so its outer electrons are in the 3p
subshell. What about an atom of nickel, Ni, (row
4)? It’s in the d area. That means its outer electrons
go into the (4 − 1)d or 3d subshell.

Step    2.          Now we  have    2   electrons   in  the lone    orbital of  the 1s  subshell.
Since no orbital can hold 3 electrons, we need to go to a different (higher
energy) subshell for the next addition.
Step 3. Follow the numbers to lithium (Li) and then beryllium (Be);
Free download pdf