Cracking the SAT Chemistry Subject Test

(Marvins-Underground-K-12) #1
pH  =   4.7 +   log 

Fourth, solve   it.

pH  =   4.7 +   log 
= 4.7 + log 10−1
= 4.7 + (−1)
= 3.7

Some Final Facts About Buffers


Here’s another look at the Henderson-Hasselbalch equation, but this time the
concentration terms, M, are expanded into the equivalent (moles/V).


pH  =   log 

Since HA(aq) and A−(aq) are in the same solution, the volumes of both V(HA)


and V(A−) must be equal. Therefore, volume cancels out, leaving

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