Everything Maths Grade 10

(Marvins-Underground-K-12) #1

Step 3: Check the answer by substituting the solution back into the original equation


LHS= 4[2(4)9]4(4)


= 4(89) 16


= 4(1) 16


= 4 16


= 20


RHS= 46(4)


= 4 24


= 20


)LHS=RHS. Since both sides are equal, the answer is correct.


Worked example 2: Solving linear equations


QUESTION


Solve forx:


2 x
3 x+ 1

= 2


SOLUTION


Step 1: Multiply both sides of the equation by(3x+ 1)


Division by 0 is undefined so there must be a restriction:


(


x̸=^13

)


.


2 x
3 x+ 1

= 2


(2x) = 2(3x+ 1)

Step 2: Expand the brackets and simplify


2 x= 6x+ 2
x 6 x= 2 2
7 x= 0

Step 3: Divide both sides by 7


x=

0


7


x= 0

Step 4: Check the answer by substituting the solution back into the original equation


LHS=


2 (0)


3(0) + 1


= 2


=RHS


Since both sides are equal, the answer is correct.


76 4.2. Solving linear equations
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