Everything Maths Grade 10

(Marvins-Underground-K-12) #1
Worked example 3: Solving linear equations

QUESTION


Solve fora:
2 a 3
3


 3 a=

a
3

SOLUTION


Step 1: Multiply the equation by the common denominator 3 and simplify


2 a 3  9 a=a
7 a3 =a

Step 2: Rearrange the terms and simplify


 7 aa= 3
8 a= 3

Step 3: Divide both sides by 8


a=

3


8


Step 4: Check the answer by substituting the solution back into the original equation


LHS =


2


(


^38


)


3


3


3


(



3


8


)


=


(


^34


)


^124


3


+


9


8


=


[



15


4





1


3


]


+


9


8


=


5


4


+


9


8


=


10


8


+


9


8


=


1


8


RHS=


^38


3


=


^38


3


=


3


8





1


3


=


1


8


)LHS=RHS. Since both sides are equal, the answer is correct.


Chapter 4. Equations and inequalities 77
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