11.7 CHAPTER 11. VECTORS
H
3 cm = 6 km
A
6 cm = 12 km B
C
2,25 cm = 5,5 km
? 4,6 cm = 9,2 km
N
S
W E
Step 7 : Apply the scale conversion
We now use the scale toconvert the length of theresultant in the scale diagram
to the actual displacement in the problem. Sincewe have chosen a scaleof 1 cm
= 2 km in this problemthe resultant has a magnitude of 9,2 km. The direction
can be specified in terms of the angle measuredeither as 072,3◦east of north or
on a bearing of 072,3◦.
Step 8 : Quote the final answer
The resultant displacement of the ship is 9,2 kmon a bearing of 072,3◦.
Example 3: Head-to-Tail GraphicalAddition II
QUESTION
A man walks 40 m East,then 30 m North.
- What was the total distance he walked?
- What is his resultantdisplacement?
SOLUTION
Step 1 : Draw a rough sketch
resultant
40 m
30 m N
S
W E
Step 2 : Determine the distancethat the man travelled
In the first part of his journey he travelled 40 m and in the second part hetravelled
30 m. This gives us a total distance travelled of40 m + 30 m = 70 m.
Step 3 : Determine his resultant displacement