CHAPTER 13. GEOMETRICAL OPTICS 13.2
1
f=
1
do+
1
di
1
4=
1
6
+
1
di
1
4−
1
6
=
1
di
3 − 2
12=
1
di
di = 12 cmStep 3 : Calculate the magnificationm =−
di
do
=−12
6
=− 2
Step 4 : Write down the properties of the image
The image is real, diis positive, inverted (because the magnification is negative)
and enlarged (magnification is > 1)Example 2: Locating the image position of a convex lens:I
QUESTIONAn object is placed 5 cmto the left of a converging lens which has a focallength of 2,5 cm.- What is the positionof the image?
- Is the image real or virtual?
SOLUTIONStep 1 : Set up the ray diagram
Draw the lens, the object and mark the focal points.Object F 1F 2
O
Step 2 : Draw the three rays