Everything Science Grade 11

(Marvins-Underground-K-12) #1

CHAPTER 17. ELECTROSTATICS 17.2


where m 1 and m 2 are the masses of the two particles, r is the distance betweenthem, and G is the
gravitational constant.


Both laws represent theforce exerted by particles (masses or charges) oneach other that interactby
means of a field.
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Example 1: Coulomb’s Law I


QUESTION

Two point-like charges carrying charges of +3× 10 −^9 C and− 5 × 10 −^9 C are 2m apart.
Determine the magnitude of the force between them and state whetherit is attractive or
repulsive.

SOLUTION

Step 1 : Determine what is required
We are required to findthe force between two point charges given the charges
and the distance between them.

Step 2 : Determine how to approach the problem
We can use Coulomb’sLaw to find the force.

F = k

Q 1 Q 2


r^2

Step 3 : Determine what is given
We are given:


  • Q 1 = +3× 10 −^9 C

  • Q 2 =− 5 × 10 −^9 C

  • r = 2m
    We know that k = 8, 99 × 109 N· m^2 · C−^2.
    We can draw a diagramof the situation.


Q 1 = +3× 10 −^9 C Q 2 =− 5 × 10 −^9 C
� �

2 m

Step 4 : Check units
All quantities are in SI units.

Step 5 : Determine the magnitude of the force
Using Coulomb’s Law we have

F = k

Q 1 Q 2


r^2

= (8, 99 × 109 N· m^2 /C^2 )

(3× 10 −^9 C)(5× 10 −^9 C)


(2m)^2
= 3, 37 × 10 −^8 N
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