CHAPTER 17. ELECTROSTATICS 17.2
where m 1 and m 2 are the masses of the two particles, r is the distance betweenthem, and G is the
gravitational constant.
Both laws represent theforce exerted by particles (masses or charges) oneach other that interactby
means of a field.
See video: VPldz at http://www.everythingscience.co.za
Example 1: Coulomb’s Law I
QUESTION
Two point-like charges carrying charges of +3× 10 −^9 C and− 5 × 10 −^9 C are 2m apart.
Determine the magnitude of the force between them and state whetherit is attractive or
repulsive.
SOLUTION
Step 1 : Determine what is required
We are required to findthe force between two point charges given the charges
and the distance between them.
Step 2 : Determine how to approach the problem
We can use Coulomb’sLaw to find the force.
F = k
Q 1 Q 2
r^2
Step 3 : Determine what is given
We are given:
- Q 1 = +3× 10 −^9 C
- Q 2 =− 5 × 10 −^9 C
- r = 2m
We know that k = 8, 99 × 109 N· m^2 · C−^2.
We can draw a diagramof the situation.
Q 1 = +3× 10 −^9 C Q 2 =− 5 × 10 −^9 C
� �
2 m
Step 4 : Check units
All quantities are in SI units.
Step 5 : Determine the magnitude of the force
Using Coulomb’s Law we have
F = k
Q 1 Q 2
r^2
= (8, 99 × 109 N· m^2 /C^2 )
(3× 10 −^9 C)(5× 10 −^9 C)
(2m)^2
= 3, 37 × 10 −^8 N