Everything Science Grade 11

CHAPTER 19. ELECTRIC CIRCUITS 19.3

Example 3: Equivalent series resistance II

QUESTION

Two resistors are connected in series. The equivalent resistance is 100 Ω. If one resistor is

10 Ω, calculate the value of the second resistor.

SOLUTION

Step 1 : Determine how to approach the problem

Since the resistors are inseries we can use:

Rs= R 1 + R 2

We are given the valueof Rsand R 1.

Step 2 : Solve the problem

Rs = R 1 + R 2

∴ R 2 = Rs− R 1

= 100Ω− 10Ω

= 90Ω

Step 3 : Write the final answer

The second resistor hasa resistance of 90 Ω.

Equivalent parallel resistance

Consider a circuit consisting of a single cell andthree resistors that are connected in parallel.

V R 1 R 2 R 3

A B C D

H G EF

� � � �

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The first principle to understand about parallel circuits is that the voltageis equal across all
components in the circuit. This is because thereare only two sets of electrically common pointsin a
parallel circuit, and voltage measured between sets of common points must always be the same at any
given time. So, for the circuit shown, the following is true:

V = V 1 = V 2 = V 3

The second principle for a parallel circuit is thatall the currents througheach resistor must add up to
the total current in the circuit.

I = I 1 + I 2 + I 3