19.3 CHAPTER 19. ELECTRIC CIRCUITS
E = V + Ir
12 = 10 + 4(r)
= 0. 5Step 3 : Write the final answer
The internal resistance of the resistor is 0.5 Ω.Exercise 19 - 2
- Calculate the equivalent resistance of:
(a) three 2 Ω resistors in series;
(b) two 4 Ω resistors in parallel;
(c) a 4 Ω resistor in series with a 8 Ω resistor;
(d) a 6 Ω resistor in series with two resistors (4 Ω and 2 Ω ) in parallel.- Calculate the total current in this circuit if both resistors are ohmic.
V =9 V
R 1 =3 Ω
R 2 =6 Ω
I
- Two ohmic resistorsare connected in series.The resistance of the one resistor is 4 Ω. What is
the resistance of the other resistor if a current of0,5 A flows through theresistors when they are
connected to a voltage supply of 6 V. - Describe what is meant by the internal resistance of a real battery.
- Explain why there isa difference between theemf and terminal voltage of a battery if the load
(external resistance in the circuit) is comparablein size to the battery’s internal resistance - What is the internal resistance of a battery ifits emf is 6 V and the voltage drop across its
terminals is 5,8 V whena current of 0,5 A flowsin the circuit when it isconnected across a
load?
More practice video solutions or help at http://www.everythingscience.co.za(1.) 00us (2.) 00ut (3.) 00uu (4.) 00uv (5.) 00uw (6.) 00ux