CHAPTER 4. ATOMICNUCLEI 4.3
See video: VPhyr at http://www.everythingscience.co.za
Example 1: Radioactive decay
QUESTION
The isotope^24195 Am undergoes radioactive decay and loses twoalpha particles.
- Write the chemical formula of the element that is produced as a result of the decay.
- Write an equation for this decay process.
SOLUTION
Step 1 : Work out the numberof protons and/or neutrons that the radioisotope loses
during radioactive decay
One α particle consists of twoprotons and two neutrons. Since two α particles
are released, the total number of protons lost is four and the total number of
neutrons lost is also four.
Step 2 : Calculate the atomic number (Z) and atomic mass number (A) of the element
that is formed.
Z = 95− 4 = 91
A = 241− 8 = 233
Step 3 : Refer to the periodic table to see which element has the atomic number that
you have calculated.
The element that has Z= 91 is protactinium (Pa).
Step 4 : Write the symbol forthe element that has formed as a result of radioactive
decay.
233
91 Pa
Step 5 : Write an equation for the decay process.
241
95 Am→
233
91 Pa + 4 protons + 4 neutrons