CHAPTER 5. THERMAL PROPERTIES AND IDEAL GASES 5.5
Example 5: General Gas Equation 1
QUESTION
At the beginning of a journey, a truck tyre has avolume of 30 dm^3 and an internal pressureof
170 kPa. The temperature of the tyre is 16◦C. By the end of the trip, the volume of the tyre
has increased to 32 dm^3 and the temperature ofthe air inside the tyre is 35 ◦C. What is the
tyre pressure at the endof the journey?
SOLUTION
Step 1 : Write down all the information that you knowabout the gas.
p 1 = 170 kPa and p 2 =?
V 1 = 30 dm^3 and V 2 = 32 dm^3
T 1 = 16◦C and T 2 = 40◦C
Step 2 : Convert the known values to SI units if necessary.
Here, temperature mustbe converted into Kelvin, therefore:
T 1 = 16 + 273 = 289 K
T 2 = 40 + 273 = 313 K
Step 3 : Choose a relevant gas law equation that will allow you to calculate theunknown
variable.
Use the general gas equation to solve this problem:
p 1 × V 1
T 1
=
p 2 × V 2
T 2
Therefore,
p 2 =
p 1 × V 1 × T 2
T 1 × V 2
Step 4 : Substitute the known values into the equation.Calculate the unknownvariable.
p 2 =
170 kPa× 30 dm^3 × 313 K
289 K× 32 dm^3
= 173 kPa
The pressure of the tyreat the end of the journeyis 173 kPa.