Cracking the SAT Physics Subject Test

(Marvins-Underground-K-12) #1

charges on all the plates will have the same magnitude.


If the top and bottom capacitors have capacitances of C 1 and C 2 , respectively, then


the potential difference across the top capacitor is ∆V 1 = Q/C 1 , and the potential


difference across the bottom capacitor is ∆V 2 = Q/C 2. The total potential difference


across the combination is ∆V 1 + ∆V 2 , which equals ∆V. Therefore, the equivalent


capacitance, CS, must be

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