CHAPTER 4. ELECTROCHEMICAL REACTIONS 4.4
- Metal ions at the bottom of the table are goodat picking up electrons.They are
easily reduced and are therefore good oxidising agents. - The reducing ability (i.e. the ability to act as areducing agent) of the metals in
the table increases as you move up in the table. - The oxidising ability ofmetals increases as you move down in the table.
Tip
Learning to understand
the question in a prob-
lem.
Before you tackle this
problem, make sure you
understand exactly what
the question is asking.
If magnesium is able to
displace silver from a so-
lution of silver nitrate,
this means that magne-
sium metal will form
magnesium ions and the
silver ions will become
silver metal. In other
words, there will now
be silver metal and a so-
lution of magnesium ni-
trate. This will only hap-
pen if magnesium has
a greater tendency than
silver to form ions. In
other words, what the
question is actually ask-
ing is whether magne-
sium or silver forms ions
more easily.
Example 2: Using the table of Standard Electrode Potentials
QUESTION
The following half-reactions take place in an electrochemical cell:
Cu2++ 2e−� Cu
Ag−+ e−� Ag
Which of these reactions will be the oxidationhalf-reaction in the cell and
which will be the reduction half-reaction?
SOLUTION
Step 1 : Determine the electrode potential for each metal
From the table of standard electrode potentials,the electrode po-
tential for the copper half-reaction is +0.34 V. The electrode po-
tential for the silver half-reaction is +0.80 V.
Step 2 : Use the electrode potential values to determine which metal is
oxidised and which is reduced
Both values are positive,but silver has a higher positive electrode
potential than copper. This means that silver does not form ions
easily, in other words, silver is more likely to be reduced. Cop-
per is more likely to be oxidised and to form ions moreeasily
than silver. Copper is the oxidation half-reactionand silver is the
reduction half-reaction.