Everything Science Grade 12

(Marvins-Underground-K-12) #1

CHAPTER 6. MOTIONIN TWO DIMENSIONS 6.3


Step 2 : Use conservation of momentum to solve the problem. First find
the initial total momentum:
Total initial momentum= Total final momentum.
But we have a two dimensional problem, and weneed to break up
the initial momentum into x and y components. Remember that
momentum is a vectorand has direction whichwe will indicate
with a ’+’ or ’-’ sign.

pix = pfx
piy = pfy

For Player 1:

pix 1 = m 1 vi 1 x= 80× (−5)× cos 75◦
piy 1 = m 1 vi 1 y= 80× 5 × sin 75◦

For Player 2:

pix 2 = m 2 vi 2 x= 80× 6 × cos 60◦
piy 2 = m 2 vi 2 y= 80× 6 × sin 60◦

Step 3 : Now write down whatwe know about the final momentum:
For Player 1:

pfx 1 = m 1 vfx 1 = 80× vfx 1
pfy 1 = m 1 vfy 1 = 80× vfy 1

For Player 2:

pfx 2 = m 2 vfx 2 = 80× (− 0 .3)
pfy 2 = m 2 vfy 2 = 80× 6

Step 4 : Use conservation of momentum:
The initial total momentum in the x direction is equal to thefinal
total momentum in the x direction.
The initial total momentum in the y direction is equal to thefinal
total momentum in the y direction.
If we find the final x and y components, then we can find the final
total momentum.

pix 1 + pix 2 = pfx 1 + pfx 2
− 80 × 5 cos 75◦+ 80× 6 × cos 60◦ = 80× vfx 1 + 80× (− 0 .3)

vfx 1 =
− 80 × 5 cos 75◦+ 80× 6 × cos 60◦
80

80 × (− 0 .3)


80


vfx 1 = 2. 0 ms−^1

piy 1 + piy 2 = pfy 1 + pfy 2
80 × 5 × sin 75◦+ 80× 6 × sin 60◦ = 80× vfy 1 + 80× 6

vfy 1 =

80 × 5 sin 75◦+ 80× 6 × sin 60◦
80

80 × 6


80


vfy 1 = 4. 0 ms−^1
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