CHAPTER 6. MOTIONIN TWO DIMENSIONS 6.4
- Mass of ball 1, m 1 = 0.3 kg.
- Mass of ball 2, m 2 = 0.3 kg.
- Initial velocity of ball 1, vi 1 = 0 m·s−^1.
- Initial velocity of ball 2, vi 2 = 2 m·s−^1.
- Final velocity of ball 2, vf 2 = 0 m·s−^1.
- The collision is elastic.
All quantities are in SI units. We need to find the final velocity
of ball 1, vf 1. Since the collision is elastic, we know that - momentum is conserved, m 1 vi 1 + m 2 vi 2 = m 1 vf 1 +
m 2 vf 2 - energy is conserved,^12 (m 1 v^2 i 1 + m 2 v^2 i 2 ) =^12 (m 1 v^2 f 1 +
m 2 v^2 f 2 )
Step 2 : Choose a frame of reference
Choose to the right as positive.
Step 3 : Draw a rough sketch of the situation
2
m 2 , vi 2
1
m 1 , vi 1
2
m 2 , vf 2
1
m 1 , vf 1
Before collision After collision
Step 4 : Solve the problem
Momentum is conserved. Therefore:
pi = pf
m 1 vi 1 + m 2 vi 2 = m 1 vf 1 + m 2 vf 2
(0,3)(0) + (0,3)(2) = (0,3)vf 1 + 0
vf 1 = 2 m· s−^1
The final velocity of ball 1 is 2 m·s−^1 to the right.
Example 9: Another Elastic Collision
QUESTION
Consider 2 marbles. Marble 1 has mass 50 g and marble 2 has mass 100 g.
Edward rolls marble 2 along the ground towards marble 1 in the positive x-
direction. Marble 1 is initially at rest and marble2 has a velocity of 3 m·s−^1 in
the positive x-direction. After they collide elastically, both marbles are moving.