CHAPTER 6. MOTIONIN TWO DIMENSIONS 6.4
This is an inelastic collision where momentum is conserved.
The momentum before= the momentum after.
The momentum after can be calculated by drawing a vector dia-
gram.
Step 2 : Calculate the momentum before the collision
p 1 (before) = m 1 vi 1 = (0,2)(3) = 0,6 kg· m·s−^1 east
p 2 (before) = m 2 vi 2 = (0,2)(4) = 0,8 kg· m·s−^1 south
Step 3 : Calculate the momentum after the collision.
Here we need to draw adiagram:
θ
0,6
0,8
p1+2(after)
p1+2(after) =
�
(0,8)^2 + (0,6)^2
= 1
Step 4 : Calculate the final velocity
First we have to find thedirection of the final momentum:
tan θ =
0 , 8
0 , 6
θ = 53, 13 ◦
Now we have to find themagnitude of the final velocity:
p1+2 = m1+2vf
1 = (0,2 + 0,2)vf
vf = 2,5 m· s−^153 , 13 ◦South of East
Exercise 6 - 3
- A truck of mass 4500 kg travelling at 20 m·s−^1 hits a car from behind.The car
(mass 1000 kg) was travelling at 15 m·s−^1. The two vehicles, now connected
carry on moving in the same direction.