CHAPTER 8. WORK, ENERGY AND POWER 8.2
applied force parallel tothe ground is
F|| = F· cos(60◦)
= 10 N· cos(60◦)
= 5 N
Step 4 : Substitute and calculate the work done
Now we can calculate the work done on the box:
W = F�s
= (5 N)(5 m)
= 25 J
Note that the answer ispositive as the component of the force F�
is in the same directionas the motion.
Exercise 8 - 1
- A 10 N force is applied to push a block across a friction free surface for a dis-
placement of 5.0 m to the right. The block hasa weight of 20 N. Determine the
work done by the following forces: normal force, weight, applied force.
N
Fg
Fapp
- A 10 N frictional force slows a moving blockto a stop after a displacement of 5.0
m to the right. The block has a weight of 20 N.Determine the work done by the
following forces: normal force, weight, frictional force.
N
Fg
Ffriction
- A 10 N force is applied to push a block across a frictional surfaceat constant
speed for a displacement of 5.0 m to the right.The block has a weightof 20 N
and the frictional force is10 N. Determine the work done by the followingforces:
normal force, weight, frictional force.
N
Fg
Ffriction Fapp