8.3 CHAPTER 8. WORK, ENERGY AND POWER
- Calculate the workdone by the hammer, W 1 , when
dropped from h 1 using:
W 1 = Fg· h 1.
- Calculate the workdone by the hammer, W 2 , when
dropped from h 2 using:
W 2 = Fg· h 2.
- Compare W 1 and W 2
- Calculate potential energy at h 1 and h 2 and compare us-
ing:
PE = m· g· h. (8.2)
Step 3 : Calculate W 1
W 1 = Fg· h 1
= m· g· h 1
= (2 kg)(9.8 m· s−^2 )(10 m)
= 196 J
Step 4 : Calculate W 2
W 2 = Fg· h 2
= m· g· h 2
= (2 kg)(9.8 m· s−^2 )(5 m)
= 98 J
Step 5 : Compare W 1 and W 2
We have W 1 =196 J and W 2 =98 J. W 1 > W 2 as required.
Step 6 : Calculate potential energy
From 8.2, we see that:
PE = m· g· h
= Fg· h
= W
This means that the potential energy is equal tothe work done.
Therefore, PE 1 > PE 2 , because W 1 > W 2.
This leads us to the work-energy theorem.