Chapter 5 e X P O N e N T S a N D r O O T S 97DeMYSTiFieD / algebra DeMYSTiFieD / HuttenMuller / 000-0 / Chapter 5still struggling
be careful, Properties 1 and 2 are easily confused.
4432 ⋅ == 4432 +^53 and( 44 )^23 ==()^264?
Property 4 a^0 = 1
Any nonzero number raised to the zero power is one. We will see that this is
true by Property 2 and the fact that any nonzero number over itself is one.
1 16
164
4442
2
====^22 −^0 From this we see that 4^0 must be 1.PRACTICE
Rewrite using a single exponent.- x
x
8
2 =- ()x^32 =
- yy^73 =
- xx^10 =
- x
x
3
2 =- ()y^55 =
✔SOLUTIONS
- x
x
xx8
2
==^82 −^6- ()xx^32 ==()^32 () x^6
- yy^73 ==yy^73 +^10
- xx xx^10 ==^1011 xx^01 + =^11
- x
x
xxx3
2
==^32 −^1 =- ()yy^55 ==()()^55 y^25
PRACTICE
Rewrite using a single exponent.
8PRACTICE
Rewrite using a single exponent.