Chapter 6 FaCtoring and the distributive ProPerty 155
EXAMPLES
Determine whether to begin the factoring as (x + __ )(x + __ ), (x – __ )(x – __ ),
or (x – __ )(x + __ ).
x^2 – 4x – 5 = (x – __ )(x + __ ) or (x + __ )(x – __ )
x^2 + x – 12 = (x + __ )(x – __ ) or (x – __ )(x + __ )
x^2 – 6x + 8 = (x – __ )(x – __ )
x^2 + 4x + 3 = (x + __ )(x + __ )
PRACTICE
Determine whether to begin the factoring as (x + __ )(x + __ ), (x − __ )(x − __ ),
or (x − __ )(x + __ ).
- x^2 − 5x − 6 =
- x^2 + 2x + 1 =
- x^2 + 3x − 10 =
- x^2 − 6x + 8 =
- x^2 − 11x − 12 =
- x^2 − 9x + 14 =
- x^2 + 7x + 10 =
- x^2 + 4x − 21 =
✔SOLUTIONS
- x^2 − 5x − 6 = (x − )(x + )
- x^2 + 2x + 1 = (x + )(x + )
- x^2 + 3x − 10 = (x − )(x + )
- x^2 − 6x + 8 = (x − )(x − )
- x^2 − 11x − 12 = (x − )(x + )
- x^2 − 9x + 14 = (x − )(x − )
- x^2 + 7x + 10 = (x + )(x + )
- x^2 + 4x − 21 = (x − )(x + )
Once the signs are determined all that remains is to fill in the two blanks. We
look at all of the pairs of factors of the constant term. These pairs will be the
candidates for the blanks. For example, if the constant term is 12, we need to
EXAMPLES
Determine whether to begin the factoring as (
PRACTICE
Determine whether to begin the factoring as (