Chapter 8 linear appliCaTionS 269- 65% 25% 40%
ml+ 180 – x^
ml=^180
ml0.65x + 0.25(180 – x) = 0.40(180)
0650 25 180 04 0 180
06545025 72
04..().( )
..
.xx
xx+−=
+− =
004572
45 45
04027
27
040
675xxxx+=
−−
===..
.Add 67.5 ml of 65% acid solution to 180 – x = 180 – 67.5 = 112.5 ml of
25% solution to produce 180 ml of 40% acid solution.
- 0% 45% 30%
liters+^10
liters= x + 10^
liters0 x + 0.45(10) = 0.30(x + 10)
00 45 10 03010
045030 3
30 3
15 0xx
x+=+
+= +
−−
=.().()
..
.
.. 330
15
030
5xxx.
.==Add 5 liters of water to 10 liters of 45% alcohol solution to produce a
30% alcohol solution.