Algebra Demystified 2nd Ed

(Marvins-Underground-K-12) #1
Chapter 8 linear appliCaTionS 307

the amount of the total concentration, the amount of the second concen-
tration is “Amount of final concentration – x.” We then solve the following
equation:

(Amt of Mixture #1)(%) + (Amt of Mixture #2)(%)


= (Amt of Final Mixture)(%)


•   Solve work problems. Two workers can complete a task. We either know
how long each worker needs to complete the task working alone and are
asked how long it would take them to complete the task if they work
together, or we know how long it would take for them to complete the
task working together and are asked how long it would take one of them
to complete the task alone (with some information on how much faster
one works than the other). We let the variable represent the time we want
to find. We then solve the following equation:

111
Worker#1Time Worker#2TimeTogetherT

+=
iime

If one of the workers works alone for a while and then the other joins in
to complete the task, the numerator of the last fraction is the proportion
of the task that remains when the second worker joins in.
• Solve distance problems. Distance problems come in many forms, but all of
them are based on the formula d = rt. If two cars/runners/etc. are traveling
in the same direction, the rate at which the distance between them is
either increasing or decreasing is the difference of their two rates. If they
are traveling in opposite directions, the rate at which the distance between
them is either increasing or decreasing is the sum of their rates. We com-
pute this changing rate for r. We usually know d. We use the equation
d = rt to answer the question. For some distance problems, a trip is divided
into two parts and we know the total distance and the total time. If this is
the case, we solve one of the following:

d
r

d
r

1
1

2
2

+=Totaltime or r, t, = r 2 , t 2

where d 1 = r 1 t 1 represents one part of the trip and d 2 = r 2 t 2 represents the
other part.
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