Chapter 9 linear inequaliTieS 333
We begin by “clearing the fraction,” so we multiply each quantity by 4.
2 51
4
6
42 4
1
51
4
46
85124
111
95
< - <
<⋅- <
<-<
+++
<<
x
x
x
x
() ()
225
9
5
5
5
25
5
9
5
5 9
5
5
<<
<<
x
x ,
PRACTICE
Solve the double inequality and give your solution in interval notation.
- 14 < 2x < 20
- 5 ≤ 3x – 1 < 8
- –2 ≤ 3x – 4 < 5
- −4 < −2x + 6 < 4
- 0.12 ≤ 4x –1 < 1.8
- 4 < 3(−2x + 1) ≤ 7
- −1 < −6x + 11 < 1
8.^7
8
1
4
< x 2 ≤
- 8 ≤ 4.5x – 1 ≤ 11
- –≤ 6 +^2 <
3
x 40
- –< 1 25 – <
3
x^1
✔SOLUTIONS
- 14 220
14
2
2
2
20
2
710710
<<
<<
<< ()
x
x
x ,
PRACTICE
Solve the double inequality and give your solution in interval notation.