Algebra Demystified 2nd Ed

(Marvins-Underground-K-12) #1

424 algebra De mystif ieD


The volume of a box is 72 cm^3. Its height is 3 cm. Its length is 1.5 times its
width. What are the length and width of the box?
The formula for the volume of the box is V = LWH. The volume is 72, the
height is 3 and the length is 1.5 times the width (L = 1.5W) so the formula
becomes 72  (=  15 .)WW() 3. We now solve this equation for W.

72 15 3
72 45
72
45
16
4

2

2

2

=
=

=

=
=

(. )()
.

.

WW
W

W

W
W

The box’s width is 4 cm and its length is (1.5)(4) = 6 cm.

The surface area of a ball is 314 in^2. What is the ball’s diameter?
The formula for the surface area of a sphere is SA = 4 or^2. The area is 314, so
the formula becomes 314 = 4or^2.

314 4
314
4
314
4
5

2

2

=

=

=


o

o

o

r

r

r

r

The radius of the ball is approximately 5 inches. The diameter is twice the
radius, so the diameter is approximately 10 inches.

The manufacturer of a drinking cup that is 6 inches tall is considering
increasing its radius. The cup has straight sides (the top is the same size as
the bottom). If the radius is increased by 1 inch, the new volume would be
169.6 in^3. What is the cup’s current radius?
The formula for the volume of a right circular cylinder is V = or^2 h. The cup’s
height is 6. If the cup’s radius is increased, the volume would be 169.6.
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