Algebra Demystified 2nd Ed

(Marvins-Underground-K-12) #1
Chapter 11 QuaDraTiC appliCaTionS 433

The plane’s average speed without the wind would have been about
320 mph.



  1. Let r represent the plane’s average speed without the wind. The average
    speed from Houston to New Orleans (against the headwind) is r − 50,
    and the average speed from New Orleans to Houston (with the tailwind)
    is r + 50. The distance between Houston and New Orleans is 300 miles.
    The time in the air from Houston to New Orleans is^300
    r –  50


, and the time
in the air from New Orleans to Houston is^300
r +  50

. The time in the air
from Houston to New Orleans plus the time in the air from New Orleans
to Houston is 1 7
4


(^34)  =  hours. The equation to solve is^300
50
300
50
7
rr 4
– 


= .
The LCD is 4(r − 50)(r + 50).
45050 300
50
()rr()
r
−+



  • 45050 300
    50
    450507
    4
    1200 50
    ()() ()()
    ()
    rr
    r
    rr
    r
    −+


  • =− +
    ++ 11200 50 75050
    1200 60 000 1200 6
    ()[( )( )]
    ,
    rrr
    rr
    −=−+
    ++− 00000 7 2500
    2400 717500
    07 2400 17
    2
    2
    2
    ,( )
    ,
    =−
    =−
    =− −
    r
    rr
    rr,, 500
    r=−− ±− −−
    = ±
    ()()()(,)
    ()
    ,
    2400 2400 47 17 500
    27
    2400 576
    2
    00000 490 000
    14
    2400 6 250 000
    14
    2400 2500
    14
    3
    ,,
    ,,




  • = ± = ±
    = 550 2400 2500
    14
     −
    

    
    isnegative
    The average speed of the plane without the wind was 350 mph. We want
    the time in the air from Houston to New Orleans:^300
    50
    300
    r 350 50
    – 

    – 
    =^
    300
    300
     =  1 hour. The plane was in flight from Houston to New Orleans for
    1 hour.



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