438 algebra De mystif ieD
✔SOLUTIONS
- Let t represent the number of hours each has traveled. The plane’s
distance after t hours is 200t and the car’s distance is 45t.
a = 45tb = 200tc =164 (45t) 2 a+ (200^2 + b^2 t= ) 2 c= 164^22FIGURE 11-6()()
,,
,45 200 164
2025 40 000 26 896
42 025222
22tt
tt+=
+=
ttttt2226 896
26 896
42 025
26 896
42 025
080====, , , , ,.The car and plane will be 164 miles apart after 0.80 hours or 48 minutes.