440 algebra De mystif ieD

3. Let t represent the number of hours after the cyclist crosses the track.
   The distance traveled by the bicycle after t hours is 11t and the distance
   traveled by the train is 60t.

a = 11t

c = 244 b = 60t (11t)a (^2 2) + (60+ b^2 t)= 2 c= 244^22
FIGURE 11-8
()()
,
,
11 60 244
121 3600 59 536
3721 59
222
22
2
tt
tt
t
+=
+=
= 5536
59 536
3721
16
16
4
2
2
t
t
t
t

=

=
,
After 4 hours the cyclist and train will be 244 miles apart.

4. Let t represent the number of hours after the scooter and car left the
   parking lot. The car’s distance after t hours is 45t. The scooter’s distance
   is 24t.

c = 34 a = 24t

b = 45t

a^2 + b^2 = c^2

(24t)^2 + (45t)^2 = 34^2

FIGURE 11-9