Chapter 11 QuaDraTiC appliCaTionS 441
()()24 45 34
576 2025 1156
2601 1156
222
22
2
2
tt
tt
t
t
+=
+=
=
==
=
=
=
1156
2601
4 9 4 9 2 3
t^2
t
t
The car and scooter will be 34 miles apart after^23 of an hour or 40 minutes.
- Let t represent the number of hours after the cars passed the overpass.
The northbound car’s distance after t hours is 60t and the eastbound
car’s distance is 50t.
a = 60t c = 104
b = 50t
a^2 + b^2 = c^2
(60t)^2 + (50t)^2 = 104^2
FIGURE 11-10
()()
,
60 50 104
3600 2500 10 816
6100 10
222
22
2
tt
tt
t
+=
+=
= ,,
,
.
816
10 816
6100
2704
1525
2704
1525
133
2
2
t
t
t
t
=
=
=
≈
The cars will be 104 miles apart after about 1.33 hours or 1 hour 20 minutes.
The time will be about 5:20.