Chapter 11 QuaDraTiC appliCaTionS 441()()24 45 34
576 2025 1156
2601 1156222
22
2
2tt
tt
t
t+=
+=
=
=====1156
2601
4 9 4 9 2 3
t^2ttThe car and scooter will be 34 miles apart after^23 of an hour or 40 minutes.
- Let t represent the number of hours after the cars passed the overpass.
The northbound car’s distance after t hours is 60t and the eastbound
car’s distance is 50t.
a = 60t c = 104b = 50ta^2 + b^2 = c^2
(60t)^2 + (50t)^2 = 104^2FIGURE 11-10
()()
,60 50 104
3600 2500 10 816
6100 10222
22
2tt
tt
t+=
+=
= ,,
,.816
10 816
6100
2704
1525
2704
1525
13322ttt
t===
≈The cars will be 104 miles apart after about 1.33 hours or 1 hour 20 minutes.
The time will be about 5:20.