1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1
Section 1—Pre-Algebra
Fundamentals

Set 1(Page 2)



  1. b.Multiply the contents of each set of paren-
    theses first. Then, multiply the resulting prod-
    ucts: (15 + 32)(56 – 39) = (47)(17) = 799

  2. b.Dividing 65,715 by 4 results in 16,428 with a
    remainder of 3. Since the hundreds place is not
    5 or greater, rounding the quotient to the
    nearest thousand yields 16,000.

  3. c.Approximate 7,404 by 7,400. The quotient
    7,40074 = 100 is a good approximation of
    the quotient 7,40074.

  4. a.Using the order of operations, compute the
    quantities within each set of parentheses first.


Then, multiply left to right as such products
arise. Finally, compute sums and differences
from left to right as they arise, as follows:
12(84 – 5) – (354) = 12(79) – (162) =
948 – 162 = 786


  1. d.Computing the sum 60,000 + 800 + 2 yields
    60,802.

  2. c.Since 1127= 16 and 1128 = 14, we
    conclude that 112 is divisible by both 7 and 8.

  3. a.Rounding 162 to the nearest hundred yields
    200 (since the tens place is greater than 5), and
    rounding 849 to the nearest hundred yields
    800 (since the tens place is less than 5). Multi-
    plying 200 times 800 yields a product of
    160,000, which is an estimation of the product
    of 162 and 849.


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