1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. b.
    2.3(4 – 3.1x) = 1 – 6.13x
    9.2 – 7.13x= 1 – 6.13x
    9.2 – 7.13x+ 7.13x= 1– 6.13x+ 7.13x
    9.2 = 1 + x
    9.2 – 1 = 1 – 1 + x
    8.2 = x


Since 8.2 = ^451 , the correct choice is b.


  1. d.An application of the distributive property
    shows that 33c– 21 = 3(11c – 7). So, since
    11 c – 7 = 8, we conclude that 33c– 21 = 3(8) = 24.

  2. d.
     2 x+ ^16 x= 4
     162 x+  122 x= 4
     182 x= 4
     182 x^182 = 4^182 
    x= 6

  3. d.
    b– ^52 = –^23 
    b–^52 + ^52 = –^23 + ^52 
    b =–^46 + ^165 
    b= ^161 

  4. c.
    ^34 c– 9 = 3
    ^34 c–9 + 9 = 3 + 9
    ^34 c= 12
    ^34 c^43 = 12^43 
    c= 16

  5. b.
    ^23 a= –54


- ^23 a–^32 = –54–^32 
a= 81
158. d.
1.3 + 5x– 0.1 = –1.2 – 3x
1.2 + 5x= –1.2 – 3x
1.2 + 5x– 1.2 = –1.2 – 3x– 1.2
5 x= –2.4 – 3x
5 x+ 3x= –2.4 – 3x+ 3x
8 x= –2.4
x= –0.3
159. d.
4(4v+ 3) = 6v– 28
16 v+ 12 = 6v– 28
16 v+ 12 – 12 = 6v– 28 – 12
16 v= 6v– 40
16 v– 6v= 6v– 6v– 40
10 v= –40
v= –4
160. b.
13 k+ 3(3 – k) = –3(4 + 3k) – 2k
13 k+ 9 – 3k= – 12 – 9k– 2k
10 k+ 9 = –12 – 11k
10 k+ 9 – 9 = – 12 – 11k– 9
10 k= – 21 – 11k
10 k+ 11k= – 21 – 11k+ 11k
21 k= – 21
21 k 211 = –21 211 
k= –1

Set 11(Page 19)


  1. a.
    –2(3v+ 5) = 14
    –6v– 10 = 14
    –6v= 14 + 10 = 24
    v= –^246 = –4


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