1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. d.
    –5[x– (3 – 4x– 5) – 5x] –2^2 = 4[2 –(x–3)]
    –5[x– 3 + 4x– 5) – 5x] – 4 = 4[2 – x+ 3]
    –5[2] – 4 = 4[5 – x]
    –10 – 4 = 20 – 4x
    –14 = 20 – 4x
    –34 = –4x
    x= ––^34 ^4 = ^127 = 8.5


Set 13 (Page 22)



  1. c.
    3 x+ 2 11
    3 x 9
    x 3

  2. c.
    5 x 23
    x^253 = 4.6

  3. a.
    1 – 2x–5
    –2x–6
    x 3


(Note: Remember to reverse the inequality
sign when dividing both sides of an inequality
by a negative number.)


  1. d.All values to the right of and including –4
    are shaded. Thus, the inequality that depicts
    this situation is x –4.

  2. b.
    4 x+ 4 24
    4 x 20
    x 5

  3. a.
    –8x+ 11 83
    8 x 72
    x–9


(Note: Remember to reverse the inequality
sign when dividing both sides of an inequality
by a negative number.)


  1. c.
    –4(x– 1) 2(x+ 1)
    –4x+ 4
    2 x+ 2
    4
    6 x+ 2
    2
    6 x
    ^13 = ^26  x


The answer can be written equivalently as
x ^13 .


  1. c.
    x+ 5 3 x+ 9
    5 2 x+ 9
    –4 2 x
    –2 x


The answer can be written equivalently as
x –2.


  1. d.
    –6(x+ 1) 60
    –6x– 6 60
    –6x 66
    x –11


(Note: Remember to reverse the inequality
sign when dividing both sides of an inequality
by a negative number.)


  1. b.The right side of the inequality 2x– 4 7
    (x – 2) can be described as “the product of
    seven and the quantity two less than a number,”
    and the left side can be described as “four less
    than two times the number.” Reading from
    right to left, the quantity on the right side is
    greater thanthe one on the left. Hence, the
    correct choice is b.


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