1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

  1. b.Let x= the number of nickels in the piggy
    bank. Then there are 65 – xdimes in the bank.
    The amount contributed to the total by the
    nickels is 0.05xand the amount contributed by
    the dimes is 0.10(65 – x). Since the total in the
    bank is $5.00, we must solve the following
    equation.


0.05x+ 0.10(65 – x) = 5.00

The equation is solved as follows:

0.05x+ 0.10(65 – x) = 5.00
0.05x+ 6.5 – 0.10x= 5.00
–0.05x= –1.5
x= –– 01 .. 055 = 30

Thus, there are 30 nickels and 35 dimes in the
piggy bank.


  1. b.Let x= Lisa’s current age (in years). Lori’s
    age is 2x. The statement, “In 5 years, Lisa will
    be the same age as her sister was 10 years ago”
    can be expressed symbolically as the equation
    x+ 5 = 2x– 10, which is solved as follows:


x+ 5 = 2x– 10
x= 15

Thus, Lisa is currently 15 years old and Lori is
30 years old.

Set 19 (Page 45)



  1. b.The fact that the graph of the line is solid
    means that it is included in the solution set,
    so the inequality describing the shaded region
    must include equality (that is, it must be either
    or ). Next, since the shaded region is below
    the horizontal line y= –2, all points in the solu-
    tion set have a y-value that is less than or equal
    to –2. Hence, the inequality illustrated by this
    graph is y – 2.
    290. a.The graph of the line is solid, so it is
    included in the solution set and the inequality
    describing the shaded region must include
    equality (either or ). Next, since the graph
    of the line rises from left to right at the rate of
    two vertical units up per one horizontal unit
    right, its slope is 2. And, since it crosses the y-
    axis at (0,7), we conclude that the equation of
    the line is y= 2x+ 7. Finally, since the shaded
    region is below the liney= 2x+ 7, the inequal-
    ity illustrated by this graph isy
    2 x+ 7. This
    can be verified by choosing a point in the
    shaded region, say (0,0), and observing that
    substituting it into the inequality results in the
    true statement 0 7.

  2. b.The graph of the line is dashed, so it is not
    included in the solution set and the inequality
    describing the shaded region must not include
    equality (it must be eitheror). Next, since
    the graph of the line falls from left to right at the
    rate of four vertical units down per one horizon-
    tal unit right, its slope is –4. Since it crosses the
    y-axis at (0,–3), we conclude that the equation of
    the line is y= –4x – 3. Finally, the shaded region
    is below the liney= –4x – 3, so we conclude that
    the inequality illustrated by this graph isy
    –4x – 3. This can be verified by choosing any
    point in the shaded region, say (0,–4), and
    observing that substituting it into the inequality
    results in the true statement –4–3.
    292. c.The graph of the line is dashed, so it is not
    included in the solution set and the inequality
    describing the shaded region must not include
    equality (it must be eitheror). Next,
    since the shaded region is to the left of the ver-
    tical line x = 8, all points in the solution set
    have an x-value that is less than or equal to 8.
    Hence, the inequality illustrated by this graph
    is x 8.


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