- c.Isolate the squared expression on one side,
 take the square root of both sides, and solve
 forx:
–3x^2 = –9
x^2 = 3
x= ± 3 - b.Take the square root of both sides, and solve
 forx:
(4x+ 5)x^2 = –494 x+ 5 = ±–49= ±7i
4 x= –5 ± 7ix=- c.Take the square root of both sides, and solve
 forx:
(3x– 8)^2 = 45
3 x– 8 = ± 45 
3 x= 8 ± 45 x= =- c.Isolate the squared expression on one side,
 take the square root of both sides, and solve
 forx:
(–2x+ 1)^2 – 50 = 0
(–2x+ 1)^2 = 50
–2x+ 1 = ± 50 
–2x= –1 ± 50 
x= = =- b.Isolate the squared expression on one side,
 take the square root of both sides, and solve
 forx:
–(1 – 4x)^2 –121 = 0
(1 – 4x)^2 = –121
1 – 4x= ±–121
–4x= –1 ±–121x= = =- a.To solve the given equation graphically, let y 1
 = 5x^2 – 24,y 2 = 0. Graph these on the same set
 of axes and identify the points of intersection:
The x-coordinates of the points of intersection
are the solutions of the original equation. We
conclude that the solutions are approximately
±2.191.- d.To solve the equation graphically, let y 1 = 2x^2 ,
 y 2 = –5x– 4. Graph these on the same set of
 axes and identify the points of intersection:
The x-coordinates of the points of intersection
are the solutions of the original equation. Since
the curves do not intersect, the solutions are
imaginary.y 2 y^1–5 –4 –3 –2 –1 1 2 3 4 5
–2
–4
–6
–8
–1010
8
6
4
2y^1–4–3–2–1 1 2 3 4 y^2
–3
–6
–9
–12
–15
–18
–21
–249
6
31 ±11i
4
1 ±–121
4
–1 ±–121
–41 ±5^2 
2
1 ±^50 
2
–1 ±^50 
–28 ±3^5 
3
8 ±^45 
3–5 ±7i
4ANSWERS & EXPLANATIONS–