- a.It is known that if is such that det A= ad– bc≠0, then. Applying
this formula with A= yields the following:- c.It is known that if is such that det A= ad– bc≠0, then. Applying
this formula with A= yields the following:- d.It is known that if is such that det A= ad– bc≠0, then. Note that
the determinant ofA= is zero, so the matrix does not have an inverse.- d.It is known that if is such that det A= ad– bc≠0, then. Note that
the determinant ofA= is zero, so the matrix does not have an inverse.- a.It is known that if is such that det A= ad– bc≠0, then. Applying
this formula with A= yields the following:- b.It is known that if is such that det A= ad– bc≠0, then. Applying
this formula with A= yields the following:A^180
4
2
0
0
– – 0
1 –
21– ==>>HH^41
0
4
2
> 0 H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dHA^10
1
1
(^11)
0
1
1
– – – 1
– (^1) ==–
HH
1
1
1
0
–
–
> – H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dH3
9
2
6
–
> – H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dH3
3
2
> 2 H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dHA 11 1
2
0
1
1
2
0
1
–
––
–
––
– (^1) ==>>HH
1
2
0
1
–
> – H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dHA 21 1
2
1
0 10
– (^1) ==–– –– 21 21
HH
0
2
1
>–– 1 H
A detA
d
cb
a1
–
A a –^1 = > – H
cb
=> dHANSWERS & EXPLANATIONS–