1001 Algebra Problems.PDF

(Marvins-Underground-K-12) #1

Set 59 (Page 139)



  1. c.First, rewrite the system as the following
    equivalent matrix equation as in Problem 913:


.


Next, identify the following determinants to be
used in the application of Cramer’s rule:

So, from Cramer’s rule, we have:

Thus, the solution is x= ^2131 ,y= ^1131 .


  1. b.First, rewrite the system as the following
    equivalent matrix equation as in Problem 882:


.


Next, identify the following determinants to be
used in the application of Cramer’s rule:

So, from Cramer’s rule, we have:

Thus, the solution is x= a,y= b.


  1. b.First, rewrite the system as the following
    equivalent matrix equation as in Problem 915:


.


Next, identify the following determinants to be
used in the application of Cramer’s rule:

So, from Cramer’s rule, we have:

Thus, the solution is x= –8,y= 6.


  1. a.First, rewrite the system as the following
    equivalent matrix equation as in Problem 916:


.


Next, identify the following determinants to be
used in the application of Cramer’s rule:

So, from Cramer’s rule, we have:

Thus, the solution is x= –7,y= 5.

y===DDy –– 15 5

x===DDx –– 17 – 7

D^2 ()( ) ()()


12


(^1) 22 11 5



  • y==–– =–


Dx==–^1213 ()() ( )() 11 ––23 7=

D==^2131 ()() ()() 21 –– 13 = 1


x
y

2


1


3


1


1


– 2


>>>HH H=


y===DDy –– 16 6

x===DDx –^81 – 8

D ()() ()()


1


2


4


y== 3 12 –– 24 = 6

Dx==^4223 ()() ()() 43 – 22 8=

D==^1223 ()() ()() 13 –– 22 = 1


x
y

a
b

1


2


2


>>> 3 HH H=


y===DDy b 1 b

x===DDx a 1 a

Dy== 01 ab ()() ()() 10 bab– =

Dx==ab 10 ()() ()()aba 10 – =

D==^1010 ()() ()() 11 – 00 1=


x
y

a
b

1


0


0


>>> 1 HH H=


y== =DDy –– 2226 1311

x== =DDx –– 2246 2311

Dy==– 13 28 ( )() ()()–– 38 12 =– 26

Dx==^2875 ()() ()() 25 –– 87 = 46

D ( )() ()()


3


1


7


5 35 17 22



==–– =–


x
y

3


1


7


5


2


8


>>>– HH H=


ANSWERS & EXPLANATIONS–
Free download pdf