- c.First, rewrite the system as the following
equivalent matrix equation as in Problem 920:
.
Next, identify the following determinants to be
used in the application of Cramer’s Rule:
So, from Cramer’s rule, we have:
Thus, the solution is x= –^4265 ,y= 21 5.
- c.First, rewrite the system as the following
equivalent matrix equation as in Problem 921:
.
Next, identify the following determinants to be
used in the application of Cramer’s rule:
So, from Cramer’s rule, we have:
Thus, the solution is x= –^15 ,y= ^252 .
- b.First, rewrite the system as the following
equivalent matrix equation as in Problem 922:
.
Next, identify the following determinants to be
used in the application of Cramer’s rule:
So, from Cramer’s rule, we have:
Thus, the solution is x= –1,y= –^136 .
- a.First, rewrite the system as the following
equivalent matrix equation as in Problem 923:
.
Next, identify the following determinants to be
used in the application of Cramer’s Rule:
So, from Cramer’s rule, we have:
Thus, the solution is x= 2,y= –4.
y===DDy – 28 – 4
x===DDx 24 2
D^0 ()() ( )( )
2
4
0
00 2 4 8
–
– –– – –
y== =
Dx==– 04 –^11 ()()()()–––41 01 4=
D==––^0211 ()()()() 01 –––21 2=
x
y
0
2
1
1
4
–– 0
>>>HH H= –
y===DDy^32 – 6 –^163
x===DDx –^66 – 1
D ()() ( )( )
2
12
2
4 24 12 2 32
–
y==––=
Dx==– 42 –^03 ()()()()–––23 40 6=
D== 122 –^03 ()()()()23 120 6–– =–
x
y
2
12
0
3
2
– 4
>>>HH H= –
y==DDy^225
x==DDx – 51
D^3 ()()()()
1
5
9
– 39 15 22
–
y==––– =
Dx==––^5912 ()()()() 52 –––91 1=–
D==– 13 –^12 ()()()()–––32 11 5=
x
y
3
1
1
2
5
9
–
>>>––HH H=
y==DDy 251
x==DDx 2546
D ()() ()( )
1
0
2
1 11 0 2 1
–
y==––=
Dx==–– 12 254 ()()()()–––– 225 1 4= 46
D==^1025 –^4 ()( ) ()( ) 125 ––0 4 25=
x
y
1
0
4
25
2
1
>>>––HH H=
ANSWERS & EXPLANATIONS–
