Extra Practice Answers 331
- If mJ = 80r, mM 80 r, then mA =
180 – (80r + 80r) = 20r.
- If AR = 7 cm, RM = 13 cm, and 'ARM is
isosceles, then AM = 7 cm or 13 cm.
- LG must be at least 13 cm but not more
than 21 cm.
- 'MAT cannot be a right triangle because
42 + 4^2 { 62.
- 'COW is a right triangle with right angle
O. If CW = 65 cm and CO = 25 cm, then
OW = 6522 25 3,600 60 cm.
- If 'PAT # 'POT and mA = 70r, then
mO = 70r
- 'DOG # 'CAT, and DO = 28 inches,
OG = 34 inches, and DG = 45 inches,
CT = DG = 45 inches
- PG = 27 cm
- RU = 28 cm
- mPAY = mL + mP, so 115r = 75r +
mP, and mP = 40r
14
21
18
14 378
27
x
x
x
x x x x x
814
10
14 x 10 x 80
480
20
828
- ACFH is a quadrilateral with AC FH,
AH CF and CA HA. ACFH is a rectangle.
- BJ = JK = KD = DB. BDKJ is a rhombus.
- JK GI and JI KG. JKGI is a
parallelogram.
- In rhombus BDJK, BD = 12 cm.
In parallelogram JKGI, GI = 12 cm.
- A = bh = 12 v 5 = 60 square inches
- If mA = 58r, mB = 180 – 58 = 122r.
- If BC = 29 cm and AD = 41 cm,
MN =^12 (29 + 41) =^12 (70) = 35 cm.
- If PQ RS, the trapezoid is isosceles.
If mQ = 119r, mS = mP = 180 – 119
= 61r.
- A =^12 (24 + 18) v 15 =^12 (42) v 15 =
21 v 15 = 315 cm^2
- The median =
1
2
b 1 b 2 = 15.
A^1 b 1 b 2 h 15 h 375
2
, so the height is
25 cm.
- Arc AB measures 76r, so mAPB =
1
2 (76) =
38 r.
- mQPR =
1
2 (301 – 59) =
1
2 (242) = 121r.
- mMXS = mNXT =
1
2 (24 + 52) =
1
2 (76) =
38 r.
- C = 2 v S v 7 = 14S cm.
- Diameter is 24 cm, so r = 12 cm.
A = S v 122 = 144S cm^2