248 Graphs of Linear Relations
which is the same asy= 3 x − 2When we work with the PS form, we come across another “sign-rigid” situation, but with minus signs
instead of a plus sign! The general form of the equation is alwaysy − y 0 =m(x − x 0 )It contains two minus signs, and pays no heed to whether y 0 or x 0 happen to be positive or negative. For
example, if m= 5, x 0 =−4, and y 0 =−8, theny − (−8)= 5[x − (−4)]which is the same asy+ 8 = 5(x+ 4)We must always pay close attention to signs when working with the standard forms of linear equations. It’s
easy to get them wrong! If we see, for example,y= 2 x − 4then the y-intercept is b=−4. If we seey − 3 =−4(x+ 5)then the graph contains a point whose coordinates are (x 0 ,y 0 )= (−5, 3).Here’s a challenge!
Imagine a straight line that passes through two points whose Cartesian coordinates are (x 1 ,y 1 ) and (x 2 ,y 2 ).
Derive an equation for this line in terms of the independent variable x and the dependent variable y. Call
this the two-point form of a linear equation. Consider x 1 ,x 2 ,y 1 , and y 2 to be constants.Solution
Figure 15-8 shows a generic example of this situation. The line has a negative slope, but that doesn’t make
any difference in the way things will turn out. Let’s start by calculating the slope of the line. It is Δy/Δx.
Let’s move to the right, from the point (x 1 ,y 1 ) to the point (x 2 ,y 2 ). ThenΔy=y 2 − y 1andΔx=x 2 − x 1The slope ism=Δy/Δx
= (y 2 − y 1 )/(x 2 − x 1 )