252 Two-by-Two Linear Systems
Dividing through by 4, we gety=− 2 x+ 4Now for the second equation. We begin with7 x−y= 41Subtracting 7x from each side, we get−y=− 7 x+ 41Multiplying through by −1 gives usy= 7 x− 41Mix the right sides and solve
Now let’s put the right side of the first SI equation on the left side of an equals sign, and the
right side of the second SI equation on the right side of the same equals sign. This produces a
first-degree equation in one variable:− 2 x+ 4 = 7 x− 41Now let’s solve this for x. When we subtract 7x from each side, we get− 9 x+ 4 =− 41We can subtract 4 from each side to obtain− 9 x=− 45Finally, we divide through by −9 to getx= 5Substitute and solve again
To solve for y, we can take either of the SI equations and plug in 5 for x. Let’s use the first one.
That gives usy=− 2 × 5 + 4
=− 10 + 4
=− 6We have used algebra to find that x= 5 and y=−6. We can express this as the ordered pair
(5,−6) if we imagine x as the independent variable and y as the dependent variable.