Part Two 327
- Solve the first-degree equation for x.
- Morph both equations into SI form with x all by itself on the left side of the
equals sign. - Mix the two equations to get a first-degree equation in y.
- Solve the first-degree equation for y.
Question 16-2
How can we put the following two-by-two linear system into a pair of SI equations with y all
by itself on the left side of the equals sign?
2 x−y+ 8 = 0
and
x− 3 y+ 9 = 0
Answer 16-2
By now, we’re good enough at equation manipulation to write down the steps one after
another, without having to justify everything. For the first original equation, we can
do this:
2 x−y+ 8 = 0
−y+ 8 =− 2 x
−y=− 2 x− 8
y= 2 x+ 8
and for the second original equation, we can do this:
x− 3 y+ 9 = 0
− 3 y+ 9 =−x
− 3 y=−x− 9
3 y=x+ 9
y= (1/3)x+ 3
Question 16-3
How can we combine the two equations from Answer 16-2 to get a first-degree equation and
solve the original system for x?
Answer 16-3
We can mix the right sides of the two SI equations together and then solve the resulting first-
degree equation in x by manipulation. Here it goes, one step at a time: