Algebra Know-It-ALL

(Marvins-Underground-K-12) #1
We aren’t allowed to get away with trivial solutions, such as letting all the integers be equal
to 1 or letting them all be equal to −1. But suppose that a= 7, b= 5, c= 14, and d= 10.
(This isn’t the only example we can use, but it should give you the general idea.) Then

ad / bc= (7 × 10) / (5 × 14)
= 70/70
= 1

and

bc / ad= (5 × 14) / (7 × 10)
= 70/70
= 1

Let’s “plug in” the values a= 7, b= 5, c= 14, and d= 10 to the original equation and see
what we get:

(a/b) / (c/d)= (c/d) / (a/b)

therefore

(7/5) / (14/10) = (14/10) / (7/5)

Note that 7/5 and 14/10 actually represent the same rational number. All we’ve really
done here is show that 1 = 1, in a roundabout way.

Chapter 7



  1. Figure A-1 shows a number line that covers the range of positive rational numbers from
    10 up to 100,000. To find the number of orders of magnitude, subtract the powers of 10.


10
5
100,000

104 10,000

103 1,000

10
2
100

(^10110)
Figure A-1 Illustration for the solution
to Prob. 1 in Chap. 7.
Chapter 7 607

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