If we add 18z to each side, we get
z+ 18 z≥− 18 z− 18 + 18 z
which simplifies to
19 z≥− 18
We finish by dividing each side by 19. That leaves us with
z≥−18/19
The original inequality holds true for all values of z larger than or equal to −18/19.
Chapter 12
- See Table B-1.
- See Table B-2.
- See Table B-3.
Table B-2. Solution to Prob. 2 in Chap. 12.
Statements Reasons
x/3= 6 x+ 2 This is the equation we are given
x= 3(6x+ 2) Multiply through by 3
x= 18 x+ 6 Distributive law applied to the right side
− 17 x= 6 Subtract 18x from each side
− 17 x− 6 = 0 Subtract 6 from each side
17 x+ 6 = 0 Multiply through by −1 and apply
the distributive law to the right side,
obtaining a more elegant equation
Chapter 12 623
Table B-1. Solution to Prob. 1 in Chap. 12.
Statements Reasons
4x+ 4 = 2x − 2 This is the equation we are given
2 x+ 4 =−2 Subtract 2 x from each side
2 x+ 6 = 0 Add 2 to each side