Easy Algebra Step-by-Step

(Marvins-Underground-K-12) #1

132 Easy Algebra Step-by-Step


Solution
a. 4 x^2 − 11 x− 3
Step 1. Identify the coeffi cients a, b, and c and
then fi nd two factors of ac whose sum is b.
a = 4, b = −11, and c = − 3
ac = 4 ⋅ − 3 = − 12
Two factors of −12 that sum to −11 are −12 and 1.

Step 2. Rewrite 4x^2 − 11 x− 3, replacing the middle term, − 11 x, with − 12 x+ 1 x.
4 x^2 − 11 x− 3 = 4 x^2 − 12 x+ 1 x− 3

Step 3. Group the terms in pairs that will yield a common factor.
= ( 4 x^2 − 12 x) + ( 1 x − 3 )

Step 4. Factor the common factor 4x out of the fi rst term and simplify the
second term.
= 4 x(x − 3 ) + (x − 3 )

Step 5. Use the distributive property to factor (x− 3) from the expression.
= (x− 3 )( 4 x+ 1 )

Step 6. Write the factored form.

xx^2111113 =()xx 33 () 44 x+ 1

b. 9 x^2 − 12 x + 4
Step 1. Identify the coeffi cients a, b, and c and then fi nd two factors of ac
whose sum is b.
a= 9, b=−12, and c= 4
ac= 9. 4 = 36
Two factors of 36 that sum to −12 are −6 and −6.

Step 2. Rewrite 9x^2 − 12 x + 4, replacing the middle term, − 12 x, with − 6 x − 6 x.
9 x^2 − 12 x + 4 = 9 x^2 − 6 x − 6 x + 4

Step 3. Group the terms in pairs that will yield a common factor.

=()− −()−

Check sign

When you’re identifying coeffi cients
for ax^2 + bx + c, keep a − symbol
with the number that follows it.
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